[LW] [LW11] Connecting the constant running hydraulic pump E12172 to the ACU-300 pump - Printable Version +- Raymarine forum (http://forum.raymarine.com) +-- Forum: Raymarine Forums (/forumdisplay.php?fid=1) +--- Forum: Autopilots (/forumdisplay.php?fid=23) +--- Thread: [LW] [LW11] Connecting the constant running hydraulic pump E12172 to the ACU-300 pump (/showthread.php?tid=7183) Pages: 1 2 |
[LW11] Connecting the constant running hydraulic pump E12172 to the ACU-300 pump - guavaberrytree - 01-09-19 05:38 PM Hi, From where do we get the supply for the motor, as there is no "motor" connection on the ACU-300? I didn't find the information in the ACU-300 installation manual. Thanks. RE: [LW11] Connecting the constant running hydraulic pump E12172 to the ACU-300 pump - Louise - Raymarine - Moderator - 01-10-19 04:38 AM Dear guavaberrytree, The ACU300 does not have a 12v power supply for a motor, the ACU300 is for solenoid drive units only. What drive unit do you have as it seems the ACU300 could be the incorrect auto-pilot for your steering system. Please find the table below for referencing suitable auto-pilots for your drive type. Many Thanks Louise RE: [LW11] Connecting the constant running hydraulic pump E12172 to the ACU-300 pump - guavaberrytree - 01-10-19 05:40 PM Thank you Louise. I have a solenoid drive unit, the Raymarine constant running hydraulic pump E12172. RE: [LW11] Connecting the constant running hydraulic pump E12172 to the ACU-300 pump - Louise - Raymarine - Moderator - 01-14-19 06:36 AM Dear guavaberrytree, Thank you for the response. I have just reviewed the manual for the E12172, the image has not been updated to reflect the ACU300. Where it states motor in the image, this should say solenoid. I will get this amended. Take the positives of Solenoid cable A and Solenoid cable B to the Solenoid A and B ports on the ACU300, then the negatives need to run back to the negative port on the ACU300. Many Thanks Louise RE: [LW11] Connecting the constant running hydraulic pump E12172 to the ACU-300 pump - guavaberrytree - 01-14-19 05:58 PM Hi Louise, I understand how to connect the solenoids, but I am not sure where to connect the motor. My question is: From where do I get the 24V for the motor? Thanks. RE: [LW11] Connecting the constant running hydraulic pump E12172 to the ACU-300 pump - Derek - Raymarine - Moderator - 01-15-19 10:15 AM Hi guavaberrytree Thank you for your feedback The motor supply is direct from distribution board where it can be correctly fused or protected by a circuit breaker. The supply can be switched by a relay so that the pump only runs when AUTO is selected, the relay can be triggered by the BYPASS connection on the ACU300. Regards Derek RE: [LW11] Connecting the constant running hydraulic pump E12172 to the ACU-300 pump - guavaberrytree - 01-15-19 05:58 PM Hi Derek, Thank you very much. I am glad to learn that I can use the "bypass" connection to trigger a relay. Best regards. RE: [LW11] Connecting the constant running hydraulic pump E12172 to the ACU-300 pump - Derek - Raymarine - Moderator - 01-16-19 07:15 AM Hi Guavaberrytree You're welcome Thanks Derek RE: [LW11] Connecting the constant running hydraulic pump E12172 to the ACU-300 pump - guavaberrytree - 01-25-19 02:24 PM Hi Derek, I have connected a relay to the "bypass" connection of the ACU 300. When I press "auto" I get the right voltage but after about 10 seconds, the voltage drops to 0V. I tried without anything connected to the "bypass" connection, I tried the 12V and the 24V positions, no difference. How can I get a constant voltage on this "bypass" connection? Thank you. RE: [LW11] Connecting the constant running hydraulic pump E12172 to the ACU-300 pump - Derek - Raymarine - Moderator - 01-28-19 07:43 AM Hi guavaberrytree The outcome you advise is expected - with nothing connected across the output terminals, the ACU identifies that there is nothing connected and so only supplies output for a short period of time, it then shuts down. We have had reports that testing with a 12v Light bulb will be enough load to enable the output to remain functional. Regards Derek |